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Exam 2 Review Solutions, 4 df = n – 1 = 49 2(0.001) = 0.002 < p-value = 2 P (T <-3.1) < 2(0.005) = 0.01 from the t table (actual p-value = 0.0030, from technology) Because the p-value is so small (would happen less than 1 time in 100 if the null hypothesis were true), we reject the null hypothesis.

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American Home Inspectors Training Institute Ltd. Also if X and Y are two random vectors in R m then E A X B Y AE X BE Y where A. Date as of change:.

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